The Secret of Nolan's Cross

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Re: The Secret of Nolan's Cross

Postby morpho79 on Thu Jan 14, 2010 7:38 pm

Could be HongKong, or could be that i misspelt it on purpose to hide something, or it could be that i was too tired and too lazy to correct errors :p

Anyone's got Nolans e-mail-addy? We couldjust ask him, unless he's scared of the Canadina Government, the aforementioned frogs, or both?
Knowledge is like jam; the less you have of it, the more you spread it around.
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Re: The Secret of Nolan's Cross

Postby D'Arcy on Thu Jan 14, 2010 10:46 pm

Morpho:

Fred does not do email. However, you can always snail-mail him by googling his Nova Scotia address in the Canada Post Directory.
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Re: The Secret of Nolan's Cross

Postby Dave Wood on Fri Jan 15, 2010 4:37 am

Morpho,
Just having a gag at the typing errors Morpho,nothing personal towards you.I think it was N4n who came up with a geological report that the swamp was natural,so maybe Petter's point Mercy was excavated by draining the swamp then refilling it,or maybe it is man-made.Personally I think the Michigan group will have a job on their hands getting permission to drain it,even a diving exploration of it wouldn't produce anything definite without being allowed to disturb the years of silt accumulated on the bottom of it.

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Re: The Secret of Nolan's Cross

Postby Dave Wood on Sun Jan 22, 2012 5:21 am

In commemoration of Francis Bacon's death on 22nd.January 1626.

Referring to the drawings shown at the beginning of the thread.The distance of the location I have is 287ft from Cone B and 218ft from the centre of the Cross.With 1 added to each of the figures then

2181 X 2871 = 6261651 (1561 1626 in reverse.)

The value of Bacon as shown 2131413 + 6261651+ 720147

= 9113211
With the distance from Cone E to the centre of the Cross of 723 gives 9113211723 and the placement of 0 between the 2 and 1 = 91132011723 which using the alphabet shown spells January.The length of the Cross at 870ft as 87 - 65 (his age) = 22,giving the date of the 22nd.January 1626.

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Re: The Secret of Nolan's Cross

Postby Dave Wood on Sat Jan 28, 2012 6:28 am

A slight amendment to the above,and an apology,I was referring to his birth date of 22nd.January,1561.
Old age creeping in I think :( .His date of death to follow on the 9th.April.

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Re: The Secret of Nolan's Cross

Postby Dave Wood on Sat Jan 28, 2012 7:57 am

Referring to the drawing again,the distances from the location mentioned above to Cones A,B,C and D are 135ft,287ft,522ft and 617ft respectively,giving a total of 1561.The distance to Cone E is 906ft and the Cross arm from B to C 720ft giving 1626.
The five boulders unearthed by Petter Amundsen that form the Tree of Life with Nolan's Cross,the distances to each 510ft,670ft,784ft,897ft and 1186ft total 4047, and the distance to the centre of the Cross is 218ft.2468ft is the total to the Cones of the Cross + 4047 + 218 = 6733.The numerical value for Francis 67, Bacon 33.Born 1561, died 1626.

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Re: The Secret of Nolan's Cross

Postby Dave Wood on Sun Feb 05, 2012 2:11 am

From Cone C continue the line through Cone B till it intersects the N-S line through the apex stone of the Welling Triangle,the distance from that point to Cone C being 1967ft.The distance from that point to the location I have given previously is 1486ft.
The form of gematria the designer of this has used is the use of 0 interspersed between figures,and by the addition or subtraction of both gives the required figure that he wants to show.
in this case 1090607 + 1040806 = 2131413,which as shown spells BACON.

Another example is the figure given along the stem of Nolan's Cross between Cones E,D,the centre of the Cross and A which is 294429147.
The angles given by the Welling Triangle as I will show later are 2337697836,without the 6 ,233769783.
The area of the triangle and the three 60d angles as a figure of 43666 subtracted from the 233769783 = 233726117.

294429147 - 233726117 = 60703030,the value of Francis Bacon.
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Re: The Secret of Nolan's Cross

Postby Dave Wood on Sun Feb 05, 2012 8:00 am

One more that I need to add regarding the Cross.

Using Cone B as the centre,draw a Circle of radius Cone B to Cone C,then extend the stem of the Cross to intersect that circle in the direction of Cone E to Cone A.From that point draw lines to Cones B and C and you have a perfect equilateral triangle of 720ft sides.Mark off that distance around the circumference of the circle and draw lines at each point to Cone B,connecting each point with a line,you then have a perfect Hexagram of 1346760sq.ft. half of which is 673380sq.ft signifying Francis Bacon as shown in the Welling Triangle.
The Welling Triangles role in all of this to follow,and as you will see is last but definitely not least.

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